Denote the Cantor middle thirds set by C and the product of two Cantor middle thirds sets by P. |
Recall the intersection formula: for almost all placements of
S and P in
|
dim(C ∩ P) = dim(C) + dim(P) - E |
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For E = 2 this becomes |
dim(C ∩ P) = Log(2)/Log(3) + Log(4)/Log(3) - 2 ≈ -0.107 |
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For E = 3 this becomes |
dim(C ∩ P) = Log(2)/Log(3) + Log(4)/Log(3) - 3 ≈ -1.107 |
Return to Dimension Algebra Exercises.