
| Denote the Sierpinski tetrahedron by T and the Cantor set by C. |
| Recall the intersection formula: for almost all placements of
T and C in
|
| dim(T ∩ C) = dim(T) + dim(C) - E |
|   |
| For E = 3 this becomes |
| dim(T ∩ C) = Log(4)/Log(2) + Log(2)/Log(3) - 3 = Log(2)/Log(3) - 1 ≈ -0.36907. |
Return to Dimension Algebra Exercises.