Some Algebra of Dimensions Exercises

Dimension of Products, Exercise 3 Answer

We select cubes of side lengths 1/4, 1/16, ... , 1/4n, ... noting the scaling of the Cantor middle-halves set.
Each square covering part of the gasket is the top face of cube covering part of the product.
For cubes of side length 1/4n, each cube covering part of the top face gasket is the top of a column of 2n cubes covering the product.
Because we need 9n squares of side 1/4n to cover the gasket, we need 9n⋅2n cubes of side length 1/4n to cover the product. That is,
N(1/4n) = 9n⋅2n
 
Knowing N(1/4n) we can compute the box-counting dimension:
d = limn→∞Log(N(1/4n)) / Log(1/(1/4n))
= limn→∞Log(9n⋅2n) / Log(4n)
= limn→∞( Log(9n) / Log(4n) + Log(2n) / Log(4n) )
= (Log(3) / Log(2)) + 1/2

Return to Dimension Algebra Exercises.