Some Algebra of Dimensions Exercises

Dimension of Unions, Exercise 2 Answer

We select squares of side lengths 1/3, 1/9, 1/27, ... , 1/3n, ... noting the scaling of the Cantor set.
   
N(1/3) = 2 + 3 - 1   N(1/32) = 22 + 32 - 1   N(1/33) = 23 + 33 - 1
and in general
N(1/3n) = 2n + 3n - 1
 
Knowing N(1/3n) we can compute the box-counting dimension by factoring out the larger term from the sum:
d = limn→∞Log(N(1/3n)) / Log(1/(1/3n))
= limn→∞Log(2n + 3n - 1) / Log(3n)
= limn→∞Log(3n(1 + (2/3)n - (1/3)n)) / Log(3n)
= limn→∞(Log(3n) + Log((1 + (2/3)n - (1/3)n))) / Log(3n)
= 1 + limn→∞Log((1 + (2/3)n - (1/3)n))) / n⋅Log(3)
= 1

Return to Dimension Algebra Exercises.