Random IFS
Same Picture
Because
diam(T
i
N
...T
i
1
(S)) = (√2)/(2
N
)
,
if we take N large enough that
(√2)/(2
N
) < resolution,
then the Random Algorithm will fill in the picture to the desired resolution
if all regions of address length N are visited
.
Why should the Random Algorithm do this?
Return to
Same Picture
.