| 5. (c) The interval with address 0 is |
| a1/21 + a2/22 + a3/23 + ... |
| Consequently, equating the two addresses that correspond to |
| 0/21 + 1/22 + 1/23 + 1/24 = 1/21 + 0/22 + 0/23 + 0/24 + ... = 1/2 |
| This is consistent with the familiar result from geometric series |
| 1/4 + 1/8 + 1/16 + 1/32 + ... = (1/4)(1/(1 - 1/2)) = 1/2 |
Return to Address questions.