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| Range of f is [1,infinity); domain of g is [-4,4]. |
| (Domain of g) intersect (Range of f) on the diagonal is AB. |
| Project AB horizontally to the graph of f. |
| x2 + 1 = 1 implies x = 0. |
| x2 + 1 = 4 implies x = +/- sqrt[3]. |
| Then project vertically to the x-axis. |
| The domain of g(f) is [-sqrt(3), sqrt(3)]. |
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