| Here we show that if some zn is farther than 2 from the origin, then successive iterates will grow without bound. That is, they will run away to ∞. |
| For a complex number zn = xn + i⋅yn, the absolute value is |
| |zn| = √(xn2 + yn2), |
| the distance from zn to the origin. |
| Recalling the sequence z0, z1, ... is defined
by |
| So suppose |
| Because |zn| > 2, we can write |
| |zn| = 2 + ε, |
| for some |
| Now |
| |zn2| = |zn2 + c - c| ≤ |zn2 + c| + |c| |
| So |
| |zn2 + c| ≥ |zn2| - |c| = |zn|2 - |c| |
| > |zn|2 - |zn| (because |zn| > |c|) |
| = (|zn| - 1)⋅|zn| = (1 + ε)⋅|zn| |
| That is, |zn+1| > (1 + ε)⋅|zn|. Iterating,
|
| To complete the proof that |zn| > 2 implies the sequence runs
away to infinity, observe that if |
| z0 = 0 |
| z1 = c |
| and z2 = c2 + c = c⋅(c + 1) |
| so |z2| = |c|⋅|c + 1| > |c| (noting |c + 1| > 1 because |c| > 2). |
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