t0 = 0.02l+0.16 = 0.02*10.2+0.16 = 0.364e (which one can't really reach in real - so we'll round all of these results - otherwise it will be too thin) Thus t0=0.4

Now we can calculate t1:

If we draw a line through the center of the vaulting circle (wherever the center is) which is perpendicular to the line bc, and call the intersection of these two lines x, we obtain similar triangles Cxc and bc0c (both have one right angle and one common angle - xcc0). From these, we can calculate cos((/2). We will mark angle c0bc as alpha. Angle xCb = alpha/2 :

Then

After rounding the result, to make the construction possible, we obtain t1=0.5e.

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