Pascal's Triangle and Its Relatives
Exercises
Other mods
1. (mod 4): Look at Pascal's triangle (mod 4).
Shade the squares congruent to 0 (mod 4). Shade the squares congruent
to 1 (mod 4).
Shade the squares congruent to 2 (mod 4). Shade the squares
congruent to 3 (mod 4).
Do you see a pattern? Now shade the squares congruent to 1, 2, or 3 (mod 4).
Shade the squares congruent to 0 or 2 (mod 4); shade the squares congruent to
1 or 3 (mod 4). How can we explain this pattern? Answer
2. (mod 5): Look at Pascal's triangle (mod 5).
Shade the squares congruent to 0 (mod 5). Shade the squares
congruent to 1 (mod 5).
Shade the squares congruent to 2 (mod 5). Shade the squares
congruent to 3 (mod 5).
Shade the squares congruent to 4 (mod 5). Shade the squares
congruent to 1, 2, 3,
or 4 (mod 5). Do you expect to see a clean fractal pattern with any
combination of numbers? Why or why not? Answer
3. (mod 6): Look at Pascal's triangle (mod 6).
Shade the squares congruent to 0 (mod 6). Shade the squares congruent to 1,
2, 3, 4 and 5 (mod 6). By now you should see the pattern. Which combinations
of squares will give clean fractal pictures? What other Pascal's triangle patterns do
those produce? Answer
4. (mod 7): Look at Pascal's triangle (mod 7).
What should you shade to produce simple patterns? Answer
5. (mod 8): Look at Pascal's triangle (mod 8).
What should you shade to produce simple patterns? Answer
6. (mod 9): Look at Pascal's triangle (mod 9).
What should you shade to produce simple patterns? Answer
7. (mod 10): Look at Pascal's triangle (mod 10).
What should you shade to produce simple patterns? Answer
8. (mod 15): Look at Pascal's triangle (mod 15).
What should you shade to produce simple patterns? Answer
General Patterns Do you see any differences between the Pascal's
triangle for Zn when n is prime vs when n is composite? What can you say
about the dimension of the shape obtained by shading the squares congruent to 1,
..., n-1 (mod n) when n is prime? What if n is composite? Use these
observations to generalize the fact that almost all binomial coefficients are
even. Answer
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